0=x^2/10-3x

Solution for 0=x^2/10-3x equation:

0=x^2/10-3x

We move all terms to the left:

0-(x^2/10-3x)=0


Domain of the equation: 10-3x)!=0

We move all terms containing x to the left, all other terms to the right

-3x)!=-10

x!=-10/1

x!=-10

x∈R


We add all the numbers together, and all the variables

-(x^2/10-3x)=0

We get rid of parentheses

-x^2/10+3x=0

We multiply all the terms by the denominator


-x^2+3x*10=0

We add all the numbers together, and all the variables

-1x^2+3x*10=0

Wy multiply elements

-1x^2+30x=0

a = -1; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-1)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-1}=\frac{-60}{-2}
=+30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-1}=\frac{0}{-2}
=0
$